Math, asked by YashodhanDasture, 7 months ago

if a and b are the zeros of polinomial x^2-x-4 fi d the value of 1/a+1/b-ab​

Answers

Answered by doraemon15
1

Answer:

x²-x-4=0

x²-4x-x-4=0

x(x-4)-1(x-4)=0

(x-1) (x-4)=0

x=1 x=4

Thus, sum of zeros=a+b=1+4=5

product of zeros=axb=4x1=4

Step-by-step explanation:

Now put its value in...

1÷a+1÷b-ab

1÷1+1÷4-1x4

5÷4-4

-11÷4 its value....

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