if a and b are the zeros of polinomial x^2-x-4 fi d the value of 1/a+1/b-ab
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Answer:
x²-x-4=0
x²-4x-x-4=0
x(x-4)-1(x-4)=0
(x-1) (x-4)=0
x=1 x=4
Thus, sum of zeros=a+b=1+4=5
product of zeros=axb=4x1=4
Step-by-step explanation:
Now put its value in...
1÷a+1÷b-ab
1÷1+1÷4-1x4
5÷4-4
-11÷4 its value....
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