If a and b are the zeros of the qadratic polynomial x²-6x+a,find the value of a if 3a+2b=20.
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Hey
Here is your answer,
A and B are the zeros of the x² - 6x + a = 0
A + B = 6
AB = a
3A + 2B = 20
A + 2(A + B) = 20
A + 12 = 20
so, A = 8 and B = - 2
so, a = AB = - 16
Hope it helps you!
Here is your answer,
A and B are the zeros of the x² - 6x + a = 0
A + B = 6
AB = a
3A + 2B = 20
A + 2(A + B) = 20
A + 12 = 20
so, A = 8 and B = - 2
so, a = AB = - 16
Hope it helps you!
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