If a and b are thee roots of the equation x² + ax + b = 0, then find the least value of x² + ax + b (x<R).
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Step-by-step explanation:
Step-by-step explanation:(1)=>2a+b=0 and (2)=>a=1 or b=0. Thus we have x^+x-2=0 i.e (x+1/2)^2-9/4=0. Hence minimum value of x^2+ax+b=0 is -9/4.
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