Question

If the sum of two numbers is 24 and their product is 108, then find the sum of their reciprocals ?

Answer 1

Step-by-step explanation:

Let's assume Number are = x1 and x2

x1+x2 = 24

x1 x2 = 108

1/x1 + 1/x2 = (x1+x2) /x1 x2

= 24/108 = 6/27= 2 /9

hope it helps you...☺❤✌

Answer 2

The sum of their reciprocals is $\frac{2}{9}$

Step-by-step explanation:

Let the numbers be a and y

We are supposed to find the sum of reciprocals of these two numbers

$\Rightarrow \frac{1}{x}+\frac{1}{y}$

$=\frac{y+x}{xy}$ --- A

We are given that the sum of two numbers is 24

So, $x+y = 24$

Product of two numbers is 108

So,$xy=108$

Substitute the values in A

So,$\frac{x+y}{xy}=\frac{24}{108}=\frac{2}{9}$

Hence the sum of their reciprocals is $\frac{2}{9}$

#Learn more:

If the sum of two numbers is 24 and the sum of their reciprocal is 1/5, then what is their product ?

https://brainly.in/question/758920