Question

if a and b are two digit positive integer with different values such that a > b , then the difference between the maximum and the minimum values (a+b) / (a-b) is what ? Plz answer . the answer which will come within 2 mins that answer will be marked as brainliest .
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Answer 1

Step-by-step explanation:

Let a and b are any two odd +ve integers

Hence, a=2m+1 and b=2n+1

Consider,

2a+b = 2

(2m+1)(2n+1) = 2

2m+2n+2=(m+n+1)

∴ 2

a+b is a positive integers.

Now,

2a−b = 2

(2m+1)−(2n+1) = 2

2m−2n =(m−n)

But, a>b

∴(2m+1)>(2n+1)

⇒m>n or m−n>0

∴ 2a−b >0

Hence,

2a−b is also a positive integers

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