Question

if A and B are two independent events such that p(A) = 1/7 and p(B) = 1/6 then p(A' B') is

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Answer 1

Answer:

1/42

Step-by-step explanation:

P(A) = 1/7

P(B) = 1/6

P(A'B') = 1/7 × 1/6

= 1/42

Please mark me as the brainliest if at all you think it is correct.....

Answer 2

Answer: P(A'B')= $\frac{5}{7}$

Step-by-step explanation:

• Given P(A)=$\frac{1}{7}$ and P(B)=$\frac{1}{6}$
• P(A')=$1-\frac{1}{7}$

               =$\frac{6}{7}$

• P(B)=$1-\frac{1}{6}$

               =$\frac{5}{6}$

• Now, P(A'B')=$\frac{6}{7}$×$\frac{5}{6}$

                            =$\frac{5}{7}$

• Hence, the required probability P(A'B')= $\frac{5}{7}$.

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