Question

if A and B are two sets such that n(A∪B)=50,n(A)=28 and n(B)=32, find n(A∩B)

Answer 1

$n(A∪B)=n(A) + n(B) - n(A∩B) \\ \\50=28 + 32 - n(A∩B) \\ \\ 50=60 - n(A∩B) \\ \\ n(A∩B) = 60 - 50 \\ \\ \boxed{n(A∩B) = 10}$

Answer 2

Answer:

Step-by-step explanation:

n(AUB)=

n(A)+n(B)-n(AnB)

..................................

50=28+32-n(AnB)

................................

n(AnB)=

60-50

=10

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