Question

solve the quadratic equation-a^2b^2x^2+b^2x-a^2x=0

Answer 1

so 2x=3

2x-3=0

2x+0-3=0

2x+0y-3=0

2x+0y+(-3)=0

Answer 2

$Given \: quadrtic \: equation \: is \\ a {}^{2} b {}^{2} x {}^{2} + b {}^{2} x - a {}^{2} x - 1 = 0 \\ = > b {}^{2} x(a {}^{2} x + 1) - 1(a {}^{2} x + 1) = 0 \\ = > (a {}^{2} x + 1)(b {}^{2} x - 1) = 0 \\ x = - \frac{1}{a {}^{2} } \: or \: x = \frac{1}{b {}^{2} } \\ \\ Hence, \: the \: roots \: of \: the \: given \: equtions \: are \: \frac{ - 1}{a {}^{2} } \: and \: \frac{1}{b {}^{2} } .$