If a and b are two vectors perpendicular to each other and |a| = |b| = 1, determine the angle between ( a + b ) and (2a + b ).
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Answer:
Ф = 18°
Explanation:
A.B = ABcosФ
cosФ = A.B / AB ...........( 1 )
A.B = ?
suppose A = ( a + b ) & B = (2a + b )
A.B = ( a + b ) . (2a + b ) = 2a² + b² as |a| = |b| = 1
A.B = 3
|a| = √(1)² + (1)² & IbI = √(2)² + (1)²
|a| = √2 & IbI = √5
putting vales in Eq.1
Ф = cos∧-1 (3/√10) = 18°
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