Math, asked by oflakes, 1 year ago

if a and b are zeroes of 3x²-5x-2, then find 1. (1/a) + (1/b) 2.a²b+ab²

Answers

Answered by AshPatel
1
a+b = 5/3
ab = -2/3

1) (1/a) + (1/b). Take ab as LCM
= b+a / ab
= 5/3 / -2/3
= -5/2
= -2.5

2) a^2b + ab^2. Take ab as common
= ab(a +b)
= -2/3 (5/3)
= -10/9

Hope this helps!!!
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Answered by CAPTAINPRANAV
0
case1:'a' and 'b' are roots
= 3x^2 -5x -2=0
sum of roots ,( a+b)= -(-5/3)=5/3. (-b/a)
product of roots(ab)=-2/3. (c/a)
1.1/a+1/b
=b+a/ab
=(5/3)/(-2/3)= -5/2

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