minimum number of capacitors of 2mueF each required to obtain a capacitance of 5mueF will be
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According to the question
Let each capacitor be c = 2 mueF
Total Capacitance C = 5 mueF
Let number of capacitors used be n
Thus in series connection
1/C = n/c
So
1/5 = n/2
n = 0.4
Thus
Clearly 4 capacitors are required in order to get 5 mueF
Let each capacitor be c = 2 mueF
Total Capacitance C = 5 mueF
Let number of capacitors used be n
Thus in series connection
1/C = n/c
So
1/5 = n/2
n = 0.4
Thus
Clearly 4 capacitors are required in order to get 5 mueF
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