Physics, asked by ruhi61, 1 year ago

minimum number of capacitors of 2mueF each required to obtain a capacitance of 5mueF will be

Answers

Answered by Geekydude121
0
According to the question

Let each capacitor  be c = 2 mueF
Total Capacitance   C = 5 mueF
Let number of capacitors used be n


Thus in series connection

1/C = n/c
So
1/5 = n/2
n  = 0.4
Thus  

Clearly 4 capacitors are required in order to get 5 mueF 
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