Question

If A and B are zeroes of a quadratic polynomial 6x^2 + x -2 find the value of A^2/B + B^2/A​

Answer 1

Answer:

A²/B+B²/A=37/72

Step-by-step explanation:

6x²+x-2=0

6x²-3x+4x-2=0

(6x²-3x)+(4x-2)=0

3x(2x-1)+2(2x-1)=0

(2x-1)(3x+2)=0

(2x-1=0)(3x+2=0)

x=½ and x=(-⅔)

A=½ and B=(-⅔)

A²/B+B²/A

=(½)²/(-⅔)+(-⅔)²/½

=¼/(-⅔)+(4/9)/½

=¼×(-3/2)+4/9×2

=3/(-8)+8/9

=((-27)+64)/72

=37/72