Question

if a and b can do a peice of work in 10 days .and a alone can do the 1/4 of the same work in 12 days. in how much time b alone can do the same work​

Answer 1

A alone can do 1/4 of the work in 12 days.

So the amount of work done by A alone in one day is 1/48.

Let B alone can do 1/x of the same work in one day.

A and B can complete the work in 10 days.

So the amount of work done by A and B in one day is 1/10.

Therefore,

$\longrightarrow\dfrac{1}{48}+\dfrac{1}{x}=\dfrac{1}{10}$

$\longrightarrow\dfrac{1}{x}=\dfrac{1}{10}-\dfrac{1}{48}$

$\longrightarrow\dfrac{1}{x}=\dfrac{19}{240}$

$\longrightarrow\underline{\underline{x=\dfrac{240}{19}\ days}}$