if a and b complete a work in 12 days and B and C complete same work in 15 days and a is 3 times faster than C then find how many days C need to complete that work
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Answer:
120 days
Step-by-step explanation:
1/a + 1/b = 1/12
1/b +1/c = 1/15
as a is 3 times faster than c
so one day work of c= 3a
substituting this value in equation 1 and subtracting equation 2 from 1 we get
3/c + 1/b - 1/b - 1/c = 1/12- 1/15
2/c = 1/60
c = 120 days.
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