If a and Bare the zeroes of the polynomice
6y2-7y +2
find a quadratic polynomial
whose zeros are
1 and I
B В
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Let the roots of the given equation be 'a' &'b' .
a+b=-(-7)/6=7/6. .....(1)
ab=2/6=1/3. .....(2)
Now,the required equation has roots: 1/a & 1/b.
sum of roots,S=(1/a)+(1/b)
=(a+b)/ab
=(7/6)÷(1/3). {from 1 & 2}
S =7/2. ...(3)
product of roots,P=(1/a)×(1/b)
=1/(ab)
=1÷(1/3)
P =3. ...(4)
The required equation will be of the form:
y^2 -Sy+P = y^2-(7/2)y+3=O [from 3 & 4]
=2y^2-7y+6=0
Hence,the required equation is:
2y^2 - 7y + 6 = 0
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