Question

. If
A and
Pare acute angles such that sin A=sin P then prove that angleA=angleP​

Answer 1

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Primary School Math 5 points

If A and B are acute angles such that sin a and Sin B then prove that angle A is equal to Angle B

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gaurav2013c

gaurav2013c Genius

Sin A = Sin B

=> BC / AB = AC / AB

=> BC = AC

We know that,

In a triangle the angles opposite to the equal sides are equal

So,

<A = <B

Hence Proved..

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Answer 2

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