if a angle is 30 degree more than one half of its complement find the measure of the angle
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let the angle be x
then 2nd angle= x/2 + 30
A.T.Q
x/2 +30+x=90
3x/2=90-30
3x=60×2
x= 120/3
x=40
then,angle=40/2+30
=20+30
=50
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then 2nd angle= x/2 + 30
A.T.Q
x/2 +30+x=90
3x/2=90-30
3x=60×2
x= 120/3
x=40
then,angle=40/2+30
=20+30
=50
MARK ME AS BRAILIEST
YashS123:
Bangalore
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