Question

If a, ß are the roots of ax2 - 2bx + c = 0 then a³B³ +a²B³+a³B² =​

Answer 1

Step-by-step explanation:

given a x²-2 bx+c=0 and a, ß are the roots

hence, a + ß = 2b/a

a³ B³ + a² B³ + a³ p² = a² p² (aß+B+

= (c/a)² (c/a + 2 b/ a)

= c² (c + 2b) /a³