Question

If a, ß are the roots of equation x2-5x+6=0 and a > ß then the equation with roots (a? +B)
and (a + B2) is
(a) x2-9x+99=0
(b) x2-18x+90=0
(c) x2-18x+77=0
(d) None
​

Answer 1

Answer:

Let α+3=x

∴α=x−3      (Replace x by x-3)

So the required equation is

⇒(x−3)  

2

−5(x−3)+6=0

⇒x  

2

−6x+9−5x+15+6=0      ......... (1)

⇒x  

2

−11x+30=0

Step-by-step explanation: