Question

If a, ß are the zeros of the polynomial f(x) = x2 - p(x + 1) - C
such that (a + 1) (B + 1) = 0, then c =
(a) 1
(6) 0
(c)-
(d) 2​

Answer 1

Answer:

f(x)=x

2

−p(x+1)−c=0

f(x)=x

2

−px−(p+c)=0

Since,

α,β are the zeroes of the above polynomial.

So,

α+β=p

αβ=−(p+c)

Since,

(α+1)(β+1)=0

αβ+α+β+1=0

−p−c+p+1=0

−c+1=0

c=1