Question

If a, ß are zeroes of f(x) = kx2 - 2x + 3k
such that a + b = aß, then k =

​

Answer 1

Answer:

a and b are zeroes,

From the equation we can say: Sum of zeroes = -ve co.eff. of x / co.eff. of x^2

Sum of zeros = - ( - 2 )/k

a + b = 2/k

Product of zeroes = constant term/co.eff. of x^2

ab = 3k / k

ab = 3

According to question:

= > a + b = ab

= > 2/k = 3

= > 2/3 = k

Therefore the value of k is 2/3

Answer 2

Step-by-step explanation:

Hope u understand

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