Question

if [a-b]=0.9 and ab=0.36, find the values of [a+b] and [a^2-b^2]

Answer 1

Answer:

a+b=1.5 and a2-b2=1.35

or

a+b=-1.5 and a2-b2= -1.35

Answer 2

Answer:

I hope this helps.

Step-by-step explanation:

(a - b)=0.9

ab=0.36

(a+b)^2

=(a-b)^2+4ab

=(0.9)^2+4×(0.36) [where, a-b=0.9,ab=0.36]

=2.25

(a+b)^2=2.25

or, (a+b)=√2.25

or, (a+b)= ± 1.5

(a^2-b^2)

= (a+b)(a-b)

= (±1.5) × (0.9) [where, a-b=0.9,a+b=±1.5]

= ± 1.35

Hence, the value of (a+b) is ± 1.5 and (a^2-b^2) is ±1.35.