Question

If (a+b)=0 , he value of a^2-b^2​

Answer 1

Given:-

(a+b)=0

To find:-

Value of a²-b²

Solution:-

We know that,a²-b²=(a+b)(a-b)

=>a²-b²=0(a-b)

=>a²-b²=0

Thus,value of a²-b² is 0.