If a+b= 1+ab then proove that a cube + b cube=1+a cube n cube
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a+b = 1 + ab
cubing both sides ,
(a + b ) ³ = (1 + ab)³
==> a³ + 3a²b + 3ab² + b³ = 1 + 3ab + 3a²b² + a³b³
==> a³ + b³ = - 3a²b - 3ab² + 3ab + 3a² b² +1 + a³b³
==> a³ + b³ = -3( a²b - ab² ) + 3 ( ab + a²b²) + 1 + a³b³
==> a³ + b³ = 1 + a³b³
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