if a-b=1&a2+b2=41, find the value of a+b
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Step-by-step explanation:
a=1+b
(1+b)^2+b^2=41
1+2b+b^2+b^2=41
2b^2+2b+1=41
2b^2+2b-40=0
divide by 2
b^2+b-20=0
b^2+5b-4b-20=0
b(b+5)-4(b+5)=0
b+5=0 b-4=0
therefore b=-5 and4
subs values of b
a=-4 and5
hooe it was useful....
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