Question

if a+b=1 and a^2+b^2=16 find the value of ab​

Answer 1

a²+b²=16

(a+b)²+2ab=16

(1)²+2ab= 16

1+2ab= 16

2ab=16-1

2ab= 15

ab= 15/2

ab= 7.5

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Answer 2

Answer:

Given:-

a+b=1

$a^2+b^2=16$

Solution:-

Squaring a and b we get:-

$( {a + b)}^{2} = {1}^{2}$

$= {a}^{2} + 2ab + {b}^{2} = 1$

$Substituting \: \: \: \: {a}^{2} + {b}^{2} = 16$

16+2ab=1

2ab=1-16

2ab= -15

$ab = \frac{ - 15}{2}$

ab= -7.5