If a+b=1 and a-b=7 find a^2+b^2 and ab
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Answered by
1
Answer:
-12
STEP BY STEP
−12
Given, a+b=1
Squaring both sides, we get
(a+b)
2
=1
2
=>a
2
+b
2
+2ab=1 ------------(i)
Also a−b=7
Squaring both sides, we get
(a−b)
2
=7
2
=>a
2
+b
2
−2ab=49 ------------(ii)
(i) - (ii), we get
=>(a
2
+b
2
+2ab)−(a
2
+b
2
+2ab)=1−49
=>4ab=−48
=>ab=−12
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