Math, asked by dhirapal100, 19 days ago

If a+b=1 and a-b=7 find a^2+b^2 and ab​

Answers

Answered by 0000001000000000
1

Answer:

-12

STEP BY STEP

−12

Given, a+b=1

Squaring both sides, we get

(a+b)

2

=1

2

=>a

2

+b

2

+2ab=1 ------------(i)

Also a−b=7

Squaring both sides, we get

(a−b)

2

=7

2

=>a

2

+b

2

−2ab=49 ------------(ii)

(i) - (ii), we get

=>(a

2

+b

2

+2ab)−(a

2

+b

2

+2ab)=1−49

=>4ab=−48

=>ab=−12

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