Question

if a-b=1 and ab=12 find the value of a^2+b^2

Answer 1

QUESTION :

if a-b=1 and ab=12 find the value of a^2+b^2

SOLUTION :

given that, a-b=1 and ab=12

a^2+b^2=(a-b) ^2 +2ab

$= (1) {}^{2} + 2(12) \\ = 1 + 24 \\ = 25$

Answer 2

Given:- a-b=1,ab=12

To find:- a²+b²

Proof:-

${a}^{2} + {b }^{2} = (a - b) {}^{2} + 2ab$

${1}^{2} + 2 {12} \\ 1+24 \\25$

Hence proved,,