Question

if a+b=1, then the value of a^3+b^3_3ab is​

Answer 1

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Answer 2

Answer:

a³ + b³ + 3ab = 1

Step-by-step explanation:

$= > (a + b) = 1 \\ whole \: cube \: on \: both \: sides \\ = > {(a + b)}^{3} = ( {1})^{3} \\ = > {a}^{3} + {b}^{3} + 3ab(a + b) = 1 \\ = > {a}^{3} + {b}^{3} + 3ab(1) = 1 \\ = > {a}^{3} + {b}^{3} + 3ab = 1$