Question

if a+ b= 10 and a square + b square = 58 find the value of a-b and a square- b square​

Answer 1

Answer: (a-b)= 4

(a-b)^2=16

Step-by-step explanation: A.T.Q

a+b=10

(a+b)^2= 58

we know that,   (a+b)^2= a^2+b^2+ 2ab

 Substitute the Values in it,

=> (a+b)^2  =  a^2+ b^2 + 2ab

=> 10^2 = 58+ 2ab

=> 100= 58 + 2ab

=> 2ab= 100-58

=> 2ab= 42

=> ab= 42/2

=> ab= 21

Now,

=>(a-b)^2= a^2+b^2- 2ab

=>(a-b)^2= 58- 2*21  

=> (a-b)^2= 58-42

=> (a-b)^2= 16  ............(i)

=> (a-b) = 16 Under root   (sorry I don't have these symbols in my device)

=> (a-b)= 4 ...............(ii)

Hope u understood the answer..  :)