Question

if a + b = 10 and a square
+ b square =58 find the value of a cube plus b cube​

Answer 1

Answer:370

Step-by-step explanation:

(a+b)^2 =a^2 +b^2 + 2ab

Now,

By putting the value we finally get

ab=21 .

Now,

(a+b)^3=a^3 +b^3 + 3ab(a+b).

Put the required values and then you will get your required answer.

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Answer 2

We have,
a + b = 10
Now,
$(a + b) ^{2} = (10)^{2}$
${a}^{2} + 2ab + {b}^{2} = 100$

58 + 2ab = 100. (because: a^2+b^2=58)

2ab = 100-58

ab = 42/2

ab= 21

Now again we will take,
a + b = 10
(a + b)^3 = (10)^3
a^3 + b^3 +3ab(a+b)= 1000
a^3 + b^3 +(3×21×10)= 1000
a^3 + b^3 + 630 = 1000
a^3 + b^3 = 1000 - 630
a^3 + b^3 = 370

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