Math, asked by subhadwivedi1130, 7 months ago


If a+b= 10
and a²+b² = 58 then find the
value of a3 +b3​

Answers

Answered by sonaparakh
0

Step-by-step explanation:

(a+b)^2 =a^2 +b^2+2ab

10^2=58+2ab

100-58 =2ab

ab=21

we know a^3+b^3=(a+b)^3-3ab (a+b)

10^3 -3x21 (10)

1000 -620

therefore a^3+b^3= 380

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