If a + b = 10 and ab = 16, find the value of a 2 - ab + b and a² + ab + b2
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Given : a + b = 10 ............(1)
and ab = 16 .....................(2)
It is known that,
(a + b)² = a² + 2ab + b²
Now, substituting the values of (1) and (2) in the above, we get.
⇒ (10)² = a² + 2*(16) + b²
⇒ 100 = a² + 32 + b²
⇒ a² + b² = 100 - 32
⇒ a² + b² = 68 .................(3)
Now, substituting the value of a² + b² = 68 in a² - ab + b²
⇒ 68 - 16 (as ab = 16)
⇒ 52
And, substituting the value of a² + b² = 68 in a² + ab + b²
⇒ 68 + 16
⇒ 84
Answer.
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