Question

If a+b=10 and ab=16, find the value of a²-ab+b² and a²+ab+b²

Answer 1

gn.  a+b=10 and ab=16
so [a+b]^{2}=100 = a^{2} + b^{2} +2ab
u need a^{2} +b^{2} -ab = [a+b]^{2}-3ab = 100-48 = 52
||ly a^{2} +b^{2} +ab = [a+b]^{2}-ab = 100-16 = 84

Answer 2

given that:
a+b = 10 and ab = 16


a^2 - ab +b^2

= (a+b)^2 -3ab

by putting the values
= (10)^2 -3 (16)
= 100- 48
=52
so, a^2 -ab +b^2 = 52

a^2 +ab +b^2
= (a+b)^2 - ab

again, by putting the values

= (10)^2 - 16
=100-16
=84

so, a^2 +ab +b^2 = 84