if a+b=10 and ab=16 then find the value of a^2-ab+b^2 and a^2+ab+b^2
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( a + b ) = 10
(a + b )^2 = 10^2
a^2 + b ^2 + 2ab = 100
a^2 + b^2 + 2*16 = 100
a^2 + b^2 = 100 - 32
a^2 + b^2 = 68
Now,
a^2 + b^2 = 68
a ^2 + b^2 + ab = 68 + ab
a^2 + b^2 + ab = 68 + 16 = 84 Answer
a^2 + b^2 = 68
= a ^2 + b^2 - ab = 68 - ab
= a^2 + b^2 - ab = 68 - 16 = 52 Ans .
(a + b )^2 = 10^2
a^2 + b ^2 + 2ab = 100
a^2 + b^2 + 2*16 = 100
a^2 + b^2 = 100 - 32
a^2 + b^2 = 68
Now,
a^2 + b^2 = 68
a ^2 + b^2 + ab = 68 + ab
a^2 + b^2 + ab = 68 + 16 = 84 Answer
a^2 + b^2 = 68
= a ^2 + b^2 - ab = 68 - ab
= a^2 + b^2 - ab = 68 - 16 = 52 Ans .
Sameen11111:
sorry but I don't think that your answer is correct
ohk let me check
because 100-32=68
it was a calculation mistake
i editted my ans.
recheck
so plz do it again
thanks
i editted my ans. Check it .. thanks to u too.. :)
I have seen it
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