If a + b = 10 and ab = 24, then what is the value of a3 – b3
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sum of zeroes = b/a
a+b =b/a
10 =b/a
product of zeroes = c/a
ab = c/a
24= c/a
a=1,b= 10,c=24
equation
axsquare - bx+ cx = 0
xsq - 10x + 24 = 0
xsq - (6x +4x) + 24 = 0
xsq-6x-4x+24=0
x(x-6)-4(x-4) =0
(x-4) (x-6)=0
either x=4 or x=6
a = 6,b = 4
a3-b3=
=6×6×6-4×4×4
=216-64
=152
a+b =b/a
10 =b/a
product of zeroes = c/a
ab = c/a
24= c/a
a=1,b= 10,c=24
equation
axsquare - bx+ cx = 0
xsq - 10x + 24 = 0
xsq - (6x +4x) + 24 = 0
xsq-6x-4x+24=0
x(x-6)-4(x-4) =0
(x-4) (x-6)=0
either x=4 or x=6
a = 6,b = 4
a3-b3=
=6×6×6-4×4×4
=216-64
=152
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