If a+b=10
anda^2+b^2=58then find a^3+b^3
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Step-by-step explanation:
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Answer: 370
Step-by-step explanation:
a + b = 10 a² + b² = 58.
Square on both sides
(a + b )² = (10)²
a² + b² + 2ab = 100
//substitute a² + b² value now
58 + 2ab = 100
2ab = 100 - 58 = 42
ab = 42/2 = 21.
Now let us find value of a³+ b³
we know a + b = 10
Cube on both sides.
(a + b)³ = (10)³
a³ + b³ + 3ab(a+b) = 1000.
a³ + b³ = 1000 - [3ab(a+b)] = 1000 - [3*21*10] = 370.
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