Question

If a+b=10
anda^2+b^2=58then find a^3+b^3

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer: 370

Step-by-step explanation:

a + b = 10             a² + b² = 58.

Square on both sides

(a + b )² = (10)²

a² + b² + 2ab = 100

//substitute a² + b² value now

58 + 2ab = 100

2ab = 100 - 58 = 42

ab = 42/2 = 21.

Now let us find value of a³+ b³

we know a + b = 10

Cube on both sides.

(a + b)³ = (10)³

a³ + b³ + 3ab(a+b) = 1000.

a³ + b³ = 1000 - [3ab(a+b)] = 1000 - [3*21*10] = 370.