If a + b = 11 and a2 +b2 = 61 find a3 + b3
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sipi20:
answer 341…???
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(a+b)^2= 121
a2+b2+2ab=121
61+2ab=121
ab=30
a3+b3=(a+b)3-3ab(a+b) =(11)^3-90×11=11(121-90)=11×31=341
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a2+b2+2ab=121
61+2ab=121
ab=30
a3+b3=(a+b)3-3ab(a+b) =(11)^3-90×11=11(121-90)=11×31=341
mark as brainliest
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14
here is ur answer my friend :)
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