if A + B =135° , then prove that ( cotA + 1 ) ( cot B + 1 ) = 2
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you can prove it by use this identical equation
(tanA+1) (tanB+1) =2
when A+B =45°
(tanA+1) (tanB+1) =2
when A+B =45°
Bubu301102:
(1+Cota)(1+Cotb)= 1+Cota+Cotb+CotaCotb
=1+ CotaCotb-1/Cot(a+b) + CotaCotb=1+1-CotaCotb+CotaCotb=2
So A+B=135–> Cot(A+B)= -1
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