if a+b=15and a2+b2=113,then find the value of a3+b3
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Answer:
(a+b)² = a²+b²+2ab
15² = 113 + 2ab
255-113 = 2ab
142 = 2ab
ab = 71
a³+b³ = (a+b) ( a²+b²-ab)
a³+b³ = (15) ( 113 - 71)
a³+b³ = 15 × 42
a³+b³ = 630
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