if a/b = 2/3 and b/c = 6/8,then find c:a
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Answered by
2
Answer:
(a+b)=6k
(b+c)=7k
(c+a)=8k
Now, we get addition of LHS & RHS
2a+2b+2c=21k
2(a+b+c)=21k
2(14)=21k —————- [given - (a+b+c)=14]
28=21k
k=28/21=4/3 ———————(1)
Since,
a+b+c=14
c=14-(a+b)
we have,
a+b=6k
a+b=6(4/3) ——————-from 1
a+b=8
now,
c=14-(a+b)
c=14–8
c=6
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Answered by
0
Answer:
Step-by-step explanation:
(a+b)=6k
(b+c)=7k
(c+a)=8k
Now, we get addition of LHS & RHS
2a+2b+2c=21k
2(a+b+c)=21k
2(14)=21k ——[given - (a+b+c)=14]
28=21k
k=28/21=4/3 ——(1)
Since,
a+b+c=14
c=14-(a+b)
we have,
a+b=6k
a+b=6(4/3) ——-from 1
a+b=8
now,
c=14-(a+b)
c=14–8
c=6
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