Question

If a:b = 2:3, b:c = 4:3, c:d = 3:2, then find a:b:c:d ?

Answer 1

$\longrightarrow \huge\underline \mathfrak {solution}$

Given,

A:B=2:3

A=2x,B=3x

B:C=4:3

B=4x,C=3x

Now in above two ratios in first B has 3x value and in second B has 4x value. Take LCM of 3x, 4x. You have 12x.

To make the value of B in first ratio to 12x . Multiply first ratio with 4 and in other ratio with 3.

You have,

A:B=8x:12x

and 

B:C=12x:9x

On combining these two,

A:B:C=8x:12x:9x

Now,

C:D=3:2

C=3x, D=2x

Now in above two ratios in first C has 9x value and in second C has 3x value. Take LCM of 9x, 3x. You have 9x.

To make the value of C in first ratio to 9x . Multiply first ratio with 1 and in other ratio with 3.

A:B:C=8x:12x:9x

C:D=9x:6x

On combining these two,

A:B:C:D=8x:12x:9x:6x

If eliminate x.

We have A:B:C:D=8:12:9:6

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