Question

if a/b =2/3,then find the value of 4a +3b/3b

Answer 1

QUESTION::

If a/b=2/3 then,
what is the value of 4a+3b/3b
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ANSWER::

First we have to substitute values :-

4a+3b/3b = (4×2)+$\frac{\large{3×3}}{\large{3×3}}$

=>(4×2)+$\frac{\large{(3×3)}}{\large{(3×3)}}$

=>8+$\frac{\large{9}}{\large{9}}$

HERE BOTH 9s ARE IN DIVISION FORM SO THEY WILL BE CANCELLED.

=>$\frac{\large{9}}{\large{9}}=$$\frac{\large{1}}{\large{1}}$

=>8+$\frac{\large{1}}{\large{1}}$

=>8+1

=>9 (<-------ANSWER )
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Answer 2

Answer:

above answer is wrong pls do my answer

Step-by-step explanation:

a/b=2/3 :::::a/2=b/3=k::::::::by al-tern-endo

a=2k and b=3k

3a+4b/3b=3(2k)+4(3k)/3(3k)=6k+12k/9k=18k/9k=18/9

=2/1=2:1

hope it will be helpful to you , pls mark me as b-r-a-n-I-L-I-s-t