The sum of length,breadth and depth of a rectangular parallelopiped is 19 cm and it's diagonal is 5root of 5 cm.What is its surface area?
Answers
Answered by
43
Hello Mate!
So, l + b + h = 19 __(i)
√( l² + b² + h² ) = 5√5
l² + b² + h² = 5√5²
l² + b² + h² = 125
In squaring equation (i)
l² + b² + h² + 2( lb + bh + hl ) = 361
125 + 2( lb + bh + hl ) = 361
2( lb + bh + hl ) = 236
Surface area if cuboid = 2( lb + bh + hl )
Surface area if cuboid is 236 cm²
Have great future ahead!
So, l + b + h = 19 __(i)
√( l² + b² + h² ) = 5√5
l² + b² + h² = 5√5²
l² + b² + h² = 125
In squaring equation (i)
l² + b² + h² + 2( lb + bh + hl ) = 361
125 + 2( lb + bh + hl ) = 361
2( lb + bh + hl ) = 236
Surface area if cuboid = 2( lb + bh + hl )
Surface area if cuboid is 236 cm²
Have great future ahead!
laba46:
Really you are a genius dada..Thanks a lot.
Thanks laba, always here to help
More one have dada.
Done ✅
Thanks for attempting brainliest mate!
Answered by
27
Answer:
Step-by-step explanation:
So, l + b + h = 19 __(i)
√( l² + b² + h² ) = 5√5
l² + b² + h² = 5√5²
l² + b² + h² = 125
In squaring equation (i)
l² + b² + h² + 2( lb + bh + hl ) = 361
125 + 2( lb + bh + hl ) = 361
2( lb + bh + hl ) = 236
Surface area if cuboid = 2( lb + bh + hl )
Surface area if cuboid is 236 cm²
Hope this helps by Parag
Great Answer
Similar questions