if (a+b)^2=361 and ab=-120, calculate the value of a^2+b^2
Answers
Answered by
8
It's Pretty simple,
We know that (a+b)² = a² + b² +2ab ,
Now, Subtracting 2ab on both sides,
=> (a+b)² - 2ab = a² + b² , Now we can find the answer quickly,
Given that,
(a+b)² = 361 and ab = -120,
=> 2ab = 2 * -120 = -240,
Now inputting the values in the above formula,
=> 361 + 240 = a² + b²,
=> a² + b² = 601,
Hope you understand, Have a great day !
We know that (a+b)² = a² + b² +2ab ,
Now, Subtracting 2ab on both sides,
=> (a+b)² - 2ab = a² + b² , Now we can find the answer quickly,
Given that,
(a+b)² = 361 and ab = -120,
=> 2ab = 2 * -120 = -240,
Now inputting the values in the above formula,
=> 361 + 240 = a² + b²,
=> a² + b² = 601,
Hope you understand, Have a great day !
zawahir:
thank u
Answered by
4
(a+b)^2=361
a^2+b^2+2ab=361
a^2+b^2+2(-120)=361. {given ab=-120}
a^2+b^2-240=361
a^2+b^2=361+240
a^2+b^2=601
a^2+b^2+2ab=361
a^2+b^2+2(-120)=361. {given ab=-120}
a^2+b^2-240=361
a^2+b^2=361+240
a^2+b^2=601
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