Question

If

(a -b)^2 =(a+b)
^2
, what is the value of ab?​

Answer 1

(a-b)^2=(a+b)^2

a^2+b^2-2ab=a^2+b^2+2ab

-2ab=2ab

ab=0

Answer 2

Answer:

$ab = 0$

${a}^{2} + {b}^{2} - 2ab = {a}^{2} + {b}^{2} + 2ab$