Question

If (a-b)^2+(b-c)^2+(c-a)^2=0 then what is the values of a, b, c

Answer 1

If (a-b)^2+(b-c)^2+(c-a)^2=0 then (a-b)^2=0,(a-b)=0 ,a=b.similarly (b-c)^2=0,(b-c)=0 ,b=c and (c-a)^2=0,(c-a)=0 ,c=a.So a=b=c.therefore a=1,b=1,c=1.Hope it helps.