Question

if (a-b)^2 +( c-d)^2 =0 then( a/b)+(c/d)=​

Answer 1

Step-by-step explanation:

(a-b)^2+(c-d)^2=0

Since sum of the squares is zero therefore individual is zero

so a-b=0 and c-d=0

therefore a=b and c=d

now so (a/b)+(c/d)= (b/b)+(d/d)=1+1=2

Hope this helps.