If a+b=2, find the value of a^3+b^3+6ab
Answers
Answered by
4
Answer:
8
Step-by-step explanation:
Given:
a+b=2
∴(a+b)³=2³=8
⇒a³+b³+3ab(a+b)=8
⇒a³+b³+3ab(2)=8
⇒a³+b³+6ab=8
Answered by
2
Answer:
8
Step-by-step explanation:
(a+b)^3 = 2^3
a^3+b^3+3a^2b+3ab^2=8
a^3+b^3+3ab(a+b)=8
a^3+b^3+3ab(2)=8
a^3+b^3+6ab=8
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