Question

If a=b^2x, b=c^2y and c=a^2z, prove that xyz=1/8

Answer 1

Step-by-step explanation:

a=b^2x​,b=c^2y​,c=a^2z

b=(a^2z)^2y​

[putting the value of c]

b = a ^4yz

a = b^2x

a = (a^4yz)^2x

[put the value of b obtained above]

a^1 = a^8xyz

1 = 8xyz

xyz = 1/8